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If in a triangleABC, BC=(e)/(|e|)-(f)/(|...

If in a `triangleABC, BC=(e)/(|e|)-(f)/(|f|) and AC=(2e)/(|e|): |e|ne|f|,` then the value of `cos2A+cos2B+cos2C` must be

A

`-1`

B

`0`

C

`2`

D

`(-3)/(2)`

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The correct Answer is:
A
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