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In triangle ABC the mid point of the sid...

In triangle ABC the mid point of the sides AB, BC and AC respectively (l, 0, 0), (0, m, 0) and (0, 0, n). Then, `(AB^2+BC^2+CA^2)/(l^2+m^+n^2)` is equal to

A

`2`

B

`4`

C

`8`

D

`16`

Text Solution

Verified by Experts

The correct Answer is:
C
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