Ina compound CltH and N are present in 9:1:3:5 by weight. If molecular weight of the compound is 108, then the molecular formula of the compound is:

Options

A. `C_2H_6N_2`
B. `C_3H_4N`
C. `C_6H_8N_2`
D. `C_9H_(12)N_3`

Answer

C

Explanation

(c) Ratio of no. of atoms in the molecule
`=(9)/(12):(1)/(1):(3.5)/(14)=0.75:1:0.25=3:4:1`
Empirical formula `=C_(3)H_(4)N`
`M.M.=(C_(3)H_(4)N)_(n)`
`nxx`empricial formula mass=molecular mass
`n(3xx12+4+14)=108`
`nxx54=108`
n=2
`M.F.=C_(6)H_(8)N_(2)`