How many moles of lead (II) chloride will be formed from a reaction between 6.5 g of PbO and 3.2 g of HCI?

Options

A. 0.044
B. 0.333
C. 0.011
D. 0.029

Answer

D

Explanation

(d) Writing the equation for the reaction , we get
`underset(207+16=223g)(PbO)+underset(2xx36.5=73g)(2HCl)to underset(207+71=278g)(PbCl_(2))+H_(2)O`
No. of moles of PbO=`(6.5j)/(223)=0.029`
No. of moles of HCl `=(3.2)/(36.5)=0.0877`
thus PbO is the limiting reactant 1 mole of PbO produce 1 mole of `PbCl_(2)`