Arrange the following in the order of increasing mass(atonic mass:`O=16,Cu=63,N=14)` (i) one atom of oxygen (ii)one atom of nitrogen (iii)`1xx10^(-10)`mole of oxygen (iv)`1xx10^(-10)`mole of copper

Options

A. 1IltIIIIltIV(b)
B. IltIIltIIIltIV
C. IIIltIIltIVltI(d)
D. IVltIIltIIIltI

Answer

A

Explanation

(a) Mass of `6.023xx10^(23)` atoms of oxygen =160 g
mass of one atom of oxygen
`=(160)/(6.023xx10^(23))=2.66xx10^(-23)g`
Mass of 6.023`xx10^(23)` atoms of nitrogen=14 g
mass of one atom of nitrogen
`=(14)/(6.023xx10^(23))=2.32xx10^(-23)g`
mass of `1xx10^(-10)` moile of oxygen`=16xx10^(-10)`
mass of 1 mole of copper=63g
mass of 1 mole of oxygen=16 g
mass of `1xx10^(-10)` mole of copper `=63xx1xx10^(-10)`
`=63xx10^(-10)`
so, the order increasing mass is `II lt I lt III lt IV`.