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For a d-electron, the orbital angular mo...

For a d-electron, the orbital angular mometum is

A

`sqrt(6) (h//2pi)`

B

`sqrt(2) (h//2pi)`

C

`(h//2pi)`

D

`2(h//2pi)`

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The correct Answer is:
A
The expression for orbital angular momentum is
Angular momentum `=sqrt(l(l+I)) ((h)/(2pi))`
For d orbital, l=2.
Hence, `L=sqrt(2(2+I))((h)/(2pi))=sqrt(6) sqrt((h)/(2pi))`
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