The values of Planck's constant is `6.63xx10^(-34)` Js. The velocity of light is `3.0xx10^(8) m s^(-1)`. Which value is closest to the wavelength in nanometres of a quantum of light with frequency of `8xx10^(15) s^(-1)` ?

Options

A. `5xx10^(-18)`
B. `4xx10^(1)`
C. `3xx10^(7)`
D. `2xx10^(-25)`

Answer

B

Explanation

`E=hv=(hc)/(lamda), and v=(c )/(lamda)`
`8xx10^(15)=(3.0xx 10^(8))/(lamda)`
`therefore lamda =(3.0xx10^(8))/(8xx10^(15))=0.37xx10^(-7)=37.5xx10^(-9) m=4xx10^(1)nm`