The correct set of four quantum numbers for the valenuce electons of rubidium atom (Z=37) is :

Options

A. `5, 0,0,+-(1)/(2)`
B. `5,1,0,+(1)/(2)`
C. `5,1,1,+(1)/(2)`
D. `5,0,1,+(1)/(2)`

Answer

A

Explanation

The electronic configuration of Rubidium (Rb=37) is
`1s^(2) 2s^(2) 2p^(6) 3p^(6)3d^(10)4s^(2)4p^(6)5s^(1)`
Since last electron eners in 5s orbital
Hence `n=5, l=0, m=0, s= +-(1)/(2)`