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The electron affinity of chlorine is 3.7...

The electron affinity of chlorine is 3.7 eV. I gram of chlorine is completely converted to `Cl^(-)` ion in a gaseous state. (`1 eV=23.06 " kcal mol"^(-1))`.
Energy released in the process is

A

4.8 kcal

B

7.2 kcal

C

8.2 kcal

D

2.4 kcal

Text Solution

Verified by Experts

The correct Answer is:
D
Number of moles `=(1)/(35.5)`
Given, `1 eV=23.06 "kcal mol"^(-1)`
`3.7 eV=3.7xx23.06 " kcal mol"^(-1)`
i.e., 1 mole realease energy
`=3.7xx23.06` kcal
`therefore` Energy released
`=(1)/(35.5)xx3.7xx23.06 kcal =2.4 kcal `
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