If an organic compound contain 92.3% C and 7.7% H, then number of `sp^(3),sp^(2) and sp` hybridized carbon atoms in all possible structures of compound respectively are (molecular mass=52g/mol)

Options

A. 1,2,5
B. 0,4,4
C. 0.8,4
D. none of these

Answer

C

Explanation

Let amount of compound=100g
No. of moles of `C=(92.3)/(12)=7.69=7.7`
No. of moles of `H=(7.7)/(1)=7.7`
empirical formula=CH
Empirical formula mass=12+1=13 g/mol
molecular mass=52g/mol
`n=(52)/(13)=4`
`therefore`Molecular mass=Empirical formula`xx4`
`=C_(4)H_(4)`
Possible structure