A container contains certain gas of mas 'm' at high pressure. Some of the gas has been allowed to escape from the container and after some time the pressure of the gas becomes half and its absolute temperature 2/3rd. The amount of the gas escaped is

Options

A. 2/3m
B. 1/2m
C. 1/4m
D. 1/6m

Answer

C

Explanation

(c) Gas equation is PV `=(m)/(M)RT` . . . (i)
Again `(P)/(2)V=(m_(1))/(M)R.(2)/(3)T` . . . (ii) ltbRgt divide (i) by(ii)
`2=(m)/(m_(1))xx(3)/(2)therefore m_(1)=(3)/(4)m`. Gas escaped is them `=(1)/(4)m`