A bubble of air is underwater at temperature `15^(@)C` and the pressure 1.5 bar. If the bubble rises to the surface where the temperature is `25^(@)C` and the pressure is 1.0 bar, what will happen to the volume of the bubble?

Options

A. Volume will become greater by a factor of 1.6
B. Volume will become will become greater by a factor 1.1
C. volume will become smaller by a factor of 0.70
D. volume will become greater by a factor of 2.5.

Answer

A

Explanation

(a) givne `P_(1)=1.5` bar `T_(1)=273+15=288K" "V_(1)=V`
`P_(2)=1.0` bar `T_(1)=273+25=298K` `V_(2)=?`
`(P_(1)V_(1))/(T_(1))=(P_(2)V_(2))/(T_(2))`
`(1.5xxV)/(288)=(1xxV_(2))/(298)`
`V_(2)=1.55V` i.e., volume of bulle will be almost 1.6 time to initial volume of bubble.