Equalmasses of `H_(2)O_(2)` and methane have been taken in a container of volume V at temperature `27^(@)C` in identical conditions. The ratio of the volumes of gases `H_(2):O_(2)` methane would be:

Options

A. `8:16:1`
B. `16:8:1`
C. `16:1:2`
D. `8:1:2`

Answer

C

Explanation

(c) According to Avogadro's law "At same temperature and pressure volume`prop`No. of moles"
`n_(H_(2))=(w)/(2),n_(O_(2))=(w)/(32),n_(CH_(4))=(w)/(16)`
`because V_(H_(2)):V_(O_(2)):V_(CH_(4))=n_(H_(2)):n_(O_(2)):n_(CH_(4))`
`=w/2:(w)/(32):(w)/(16)=16:1:2`