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One mole of a non-ideal gas undergoes a change of state (2.0 atm, 3.01, 95K)`to`(4.0 atm, 5.01, 245K) with a change in internal energy, `DeltaU=30.0L` atm. The change in enthalpy `DeltaH` of the process in L atm is.

A

40

B

42.3

C

44

D

Not defined because pressure is not constant

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The correct Answer is:
C
(c) `DeltaH=H_(2)-H_(1)=(E_(2)+P_(2)V_(2))-(E_(1)+P_(1)V_(1))`
`=(E_(2)-E_(1))+(P_(2)V_(2)-P_(1)V_(2))`
`=30+4xx5-2xx3=44L` atm
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