The reaction in which hydrogen perioxide acts as a reducing agent is

Options

A. `PbS+4H_(2)O_(2) to PbSO_(4)+4H_(2)O`
B. `2KI+H_(2)O_(2) to 2KOH+I_(2)`
C. `2FeSO_(4)+H_(2)SO_(4)+H_(2)O_(2) to Fe_(2)(SO_(4))_(3)+2H_(2)O`
D. `Ag_(2)O+H_(2)O_(2) to 2Ag+H_(2)O+O_(2)`

Answer

D

Explanation

In `Ag_(2)O,O.N.` of Ag is +1 and in Ag the O.N. is 0. there is gain of electrons, hence `H_(2)O_(2) ` act as a reducing agent.