`f : R to R : f (x) =1 is x is rational -1, if x is rational
show that f is many -one and into.

f : R to R : f (x) ={ underset(-1, " if x is rational ")(1 " is x is rational ") show that f is many -one and into.

Show that the function f:R rarr R:f(x)={1 if x is rational and -1, if x is irrational is many- one into

f(x)=1 for x is rational -1 for x is irrational,f is continuous on

f(x)=1 for x is rational f(x)=-1 for x irrational, f is continuous on

If f(x)={x,x is rational 1-x,x is irrational , then f(f(x)) is

If f(x)={x ,x is rational 1-x ,x is irrational ,then f(f(x)) is

If f(x)={x ,x is rational 1-x ,x is irrational ,then f(f(x)) is

If f(x)={x ,x is rational 1-x ,x is irrational ,then f(f(x)) is

Let the function f : R rarr R f(x) = {:{(1,if x is a rational)(-1, if x is irrational):}} be many one into Then f(1/2) is equal to