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lf for all x different from both 1 and 0...

lf for all x different from both 1 and 0 we have `f_1(x)=x/(x-1),f_2(x)=1/(1-x)` and for all integers `n leq 1`, we have `f_(n+2)(x)=[f_(n+1)(f_1(x))` if n is odd and `f_(n+1)(f_2(x))` if n is even then `f_4(x)` equals

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