" The solubility "A_(2)B_(3)" is "x" mol "dm^(-3)." Its "K_(sp)" is "

The solubility of A_(2)B_(3) is "x mol dm"^(-3) . Its K_(sp) is

The solubility of A_(2)B_(3) is "x mol dm"^(-3) . Its K_(sp) is

the solubility of A_(2)B_(3) is y mol dm^(-3) . Its solubility product is

The solubility of A_(2)X_(2) is x mole dm^(-3) . Its solubility product is

The solubility of A_(2)X_(5) is x mole dm^(-3) . Its solubility product is

The solubility of A_(2)X_(5) is x mole dm^(-3) . Its solubility product is

The solubility of A_2X_3 is y mol dm^(-3) Its solubility product is

For the sparingly soluble salts, an equilibrium is established between the undissolved solid unit and ions of the dissolved salt. For a solution of the salt like A_x B_y . A_x B_y =xA^(y+)+yB^(x-) K_(sp)=[A^(y+)]^x [B^(x-)]^y For precipitation to occur , the ionic product must be greater than K_(sp) . The solubility of A_2X_3 is y mol dm^(-3) . Its solubility product is