|A=[[0,-tan(alpha)/(2)],[tan(alpha)/(2),0]]" show that "(1+A)=(1-A)[[cos alpha,-sin alpha],[sin alpha,cos alpha]]

If A=,[[0,-tan((alpha)/(2))]tan((alpha)/(2)),0]], then I+A=(I-A)[[cos alpha,-sin alphasin alpha,cos alpha]]

If A=[(0, -tan""(alpha)/(2)),(tan""(alpha)/(2),0)] , then show that (I+A) =(I-A) [(cos alpha, - sin alpha),(sin alpha, cos alpha)] , where I is the identity matrix of order 2.

A=[[0,-tan((alpha)/(2))tan((alpha)/(2)),0]]then(I-A)[[cos alpha,-sin alphasin alpha,cos alpha

If A=[(0,-tan (alpha/2)),(tan (alpha/2),0)] and I is 2 xx 2 unit matrix, then (I-A)[(cos alpha,-sin alpha),(sin alpha, cos alpha)] is

If A=[(0,-tan (alpha/2)),(tan (alpha/2),0)] and I is 2 xx 2 unit matrix, then (I-A)[(cos alpha,-sin alpha),(sin alpha, cos alpha)] is

If A=[(0,-tan (alpha/2)),(tan (alpha/2),0)] and I is 2 xx 2 unit matrix, then (I-A)[(cos alpha,-sin alpha),(sin alpha, cos alpha)] is

If A=[[0,-tan alpha2,tan alpha2,tan alpha]] and I is 2xx2 unit matrix,then (I-A)[[cos alpha,sin alphasin alpha,sin alphasin alpha,sin alpha]] is (a) these

tan theta = (sin alpha-cos alpha) / (sin alpha + cos alpha)

If A = [[0,-tan alpha/2],[tan alpha/2,0]] and I is the identity matrix of order 2, show that I + A = (I - A)[[cos alpha,-sin alpha],[sin alpha,cos alpha]]