`{:(A+B+C,to,"Product",,),(Ex.No,[A],[B],[C],"Rate of reaction"),(1.,0.2,0.1,0.1,6xx10^(-5)),(2.,0.2,0.2,0.1,6xx10^(-5)),(3.,0.2,0.1,0.2,1.2xx10^(-4)),(4.,0.3,0.1,0.1,9xx10^(-5)):}`
When [A] =0.15
[B]=0.25
[C]=0.15
Rate of reaction is `Yxx10^(-5) M//s` Find Y.

Answer

6.75

Explanation

`r=k[A]^(a)[B]^(b)[C]^(c)`
`{:("by experiment no.",1 & 2,b=0),("by experiment no.",1&3,c=1),("by experiment no." ,1&4,a=1):}`
`r=K[A]^(1)[B]^(0)[C]^(1)`
From Ex. No.1 `" " 6xx10^(-5) =k(0.2)(0.1)`
`" " k=3xx10^(-3)`
Given `[A]=0.15" " [B]=0.25 " " [C]=0.15`
`r=k[A]^(1)[B]^(0)[C]^(1)`
`=3xx10^(-3)xx0.15xx1xx0.15`
`=3xx0.025xx10^(-3)`
`=6.76xx10^(-5) "mol" L^(-1) sec^(-1)`
Y=6.75