At high altitude , a body explodes at rest into two equal fragments with one fragment receiving horizontal velocity of `10 m//s`. Time taken by the two radius vectors connecting of explosion to fragments to make `90^(@)` is

At high altitude, a body explodes at rest into two equal fragments with one of the fragments receiving horizontal velocity 10 ms. The time when the radius vectors connecting point of explosion to fragments make 90^(@) is (g=10 ms^(_2))

At a certain height a body at rest explodes into two equal fragments with one fragment receiving a horizontal velocity of 10ms^(-1) . The time interval after the explosion for which the velocity vectors of the two fragments become perpendicular to each other is (g=10ms^(-2))

At a certain height a body at rest explodes into two equal fragments with one fragment receiving a horizontal velocity of 10ms^−1. The time interval after the explosion for which the velocity vectors of the two fragments become perpendicular to each other is

At a certain height a body at rest explodes into two equal fragments with one fragment receiving a horizontal velocity of 10ms^(-1) The time interval after the explosion for which the velocity vectors of the two fragments become perpendicular to each other is (g=10ms^(-2))