Let `f:R->(0,pi/6]` be defined as `f(x)=sin^-1(4/(4x^2-12x+17))` then `f(x) ` is

Let f:R -> ( 0,(2pi)/3] defined as f(x) = cot^-1 (x^2-4x + alpha) Then the smallest integral value of alpha such that, f(x) is into function is

Let f:R -> ( 0,(2pi)/3] defined as f(x) = cot^-1 (x^2-4x + alpha) Then the smallest integral value of alpha such that, f(x) is into function is

Let f:[-1,3]-> [-8, 72] be defined as, f(x) = 4x^3-12x ,then f is

Let f:R rarr(0,(2 pi)/(2)] defined as f(x)=cot^(-1)(x^(2)-4x+alpha) Then the smallest integral value of alpha such that,f(x) is into function is

Let f:[0,4pi]->[0,pi] be defined by f(x)=cos^-1(cos x). The number of points x in[0,4pi] 4satisfying the equation f(x)=(10-x)/10 is

Let f:[0,4pi]->[0,pi] be defined by f(x)=cos^-1(cos x). The number of points x in[0,4pi] 4satisfying the equation f(x)=(10-x)/10 is

Let f:[0,4pi]->[0,pi] be defined by f(x)=cos^-1(cos x). The number of points x in[0,4pi] 4satisfying the equation f(x)=(10-x)/10 is