Position of a point object is given by `x = (2)/(3)t^(3) - 4t^(2)+6t+7` (x is in meter and t is in seconds). What would be the distance travelled by object from t = 0 to instant when particle its direction of velocity for last time.

The position of a particle moving along a straight line is defined by the relation, x=t^(3)-6t^(2)-15t+40 where x is in meters and t in seconds.The distance travelled by the particle from t=0 to t=2 s is?

The position of a particle is given by x=2(t-t^(2)) where t is expressed in seconds and x is in metre. When is the object at rest?

The position of a particle is given by x=2(t-t^(2)) where t is expressed in seconds and x is in metre. When is the object at rest?

The distance travelled (in meters) by the particle from time t = 0 to t = t will be –

The position of particle 'x' with respect to time at any instant 't' along x-axis is given by equation x=9t^(2) -t^(3) where x is in meter and t is in seconds. What will be the position of this particle when particle achieves maximum speed along x-axis.

The position (in meters) of a particle moving on the x-axis is given by: x=2+9t +3t^(2) -t^(3) , where t is time in seconds . The distance travelled by the particle between t= 1s and t= 4s is m.

The position (in meters) of a particle moving on the x-axis is given by: x=2+9t +3t^(2) -t^(3) , where t is time in seconds . The distance travelled by the particle between t= 1s and t= 4s is m.

A car is moving in such a ways that the distance it covers , is given by the equations s = 4t^(2) +3t, where s, is in meters and t is in seconds . What would be the velocity and the accelerations of the car at time t=20 seconds?

Position of a particle at any instant is given by x = 3t^(2)+1 , where x is in m and t in sec. Its average velocity in the time interval t = 2 sec to t = 3 sec will be :