If `f(x)=x+1.g^(- 1)(x)=x^3+x+1 and g(f(x))=h(x)., ` then `lim_(x->1) (h^-1(x)-h^-1(1))/(x-1)` is equal to

If f(x)=x-1, g(x)=3x , and h(x)=5/x , then f^(-1)(g(h(5))) =

If f(1) =g(1)=2 , then lim_(xrarr1) (f(1)g(x)-f(x)g(1)-f(1)+g(1))/(f(x)-g(x)) is equal to

If f(1) =g(1)=2 , then lim_(xrarr1) (f(1)g(x)-f(x)g(1)-f(1)+g(1))/(f(x)-g(x)) is equal to

f(x)= x, g(x)= (1)/(x) and h(x)= f(x) g(x). If h(x) = 1 then…….

Let f(x)=x, g(x)=1//x and h(x)=f(x) g(x). Then, h(x)=1, if

If f(x)=2/(x-3),g(x)=(x-3)/(x+4) , and h(x)=-(2(2x+1))/(x^2+x-12) then lim_(x->3)[f(x)+g(x)+h(x)] is (a) -2 (b) -1 (c) -2/7 (d) 0

If f(a) = 2 , f ' (a) = 1 , g (a) = -1 , g'(a) = 2 , then lim_(x to a) (g (x) * f (a) - g (a) * f(x))/( x- a) is equal to

If f(x)=2/(x-3),g(x)=(x-3)/(x+4) , and h(x)=-(2(2x+1))/(x^2+x-12) then lim_(x->3)[f(x)+g(x)+h(x)] is (a) -2 (b) -1 (c) -2/7 (d) 0