Which one of the following will most readily be dehydrated in acidic condition?

Options

A.
B.
C.
D.

Explanation

To determine which compound will most readily be dehydrated in acidic conditions, we need to analyze the stability of the resulting alkenes formed after dehydration. The more stable the alkene, the more readily dehydration will occur.

### Step-by-Step Solution:

1. **Identify the Compounds**:
We need to look at the given options (A, B, C, D) and identify the functional groups present in each compound. The presence of -OH (hydroxyl) groups is crucial for dehydration.

2. **Protonation of Hydroxyl Group**:
In acidic conditions, the hydroxyl group (-OH) can be protonated to form a better leaving group (-OH2+). This makes it easier for the molecule to undergo dehydration.

3. **Formation of Carbocation**:
After the hydroxyl group is protonated, the molecule can lose a water molecule, leading to the formation of a carbocation. The stability of this carbocation is essential; tertiary carbocations are more stable than secondary, which are more stable than primary.

4. **Elimination to Form Alkene**:
Once the carbocation is formed, a hydrogen atom can be eliminated from an adjacent carbon to form a double bond, resulting in the formation of an alkene. The more substituted the alkene, the more stable it is due to hyperconjugation and inductive effects.

5. **Compare Stability of Alkenes**:
Evaluate the alkenes formed from each compound. The compound that forms the most stable alkene will be the one that undergoes dehydration most readily.

6. **Conclusion**:
Based on the analysis, identify which compound leads to the most stable alkene after dehydration. The compound that forms a conjugated alkene or a more substituted alkene will be the most favorable.