The major product `H` of the given reaction sequence is
`CH_(3) - CH_(2) CO - CH_(3) overset (Theta_(CN)) to G - overset (95% H_(2) SO_(4)) underset (Heat) to H`

Options

A. `CH_(3)-CH=underset(CH_(3))underset(|)(C)-COOH`
B. `CH_(3)-CH=underset(CH_(3))underset(|)(C)-CN`
C. `CH_(3)-CH_(2)-overset(OH)overset(|)underset(CH_(3))underset(|)(C)-COOH`
D. `CH_(3)-CH=underset(CH_(3))underset(|)(C)-CO-NH_(2)`

Explanation

To determine the major product \( H \) of the given reaction sequence, we will follow these steps:

### Step 1: Identify the starting material
The starting material is \( CH_3 - CH_2 - CO - CH_3 \), which can be represented as:
\[ CH_3 - CH_2 - C(=O) - CH_3 \]
This is butan-2-one.

### Step 2: Nucleophilic addition of cyanide
The reaction involves the addition of a cyanide ion \( CN^- \) to the carbonyl group. In a nucleophilic addition reaction, the cyanide ion attacks the carbon atom of the carbonyl group, leading to the formation of a cyanohydrin. The reaction can be illustrated as follows:
1. The \( CN^- \) attacks the carbonyl carbon.
2. The double bond between carbon and oxygen shifts to the oxygen, forming an alkoxide ion.

The intermediate product \( G \) can be represented as:
\[ CH_3 - CH_2 - C(CN)(OH) - CH_3 \]

### Step 3: Acidic hydrolysis
Next, we treat the intermediate \( G \) with 95% \( H_2SO_4 \) and heat it. The acidic conditions will lead to hydrolysis of the cyanide group:
1. The \( CN \) group will be converted to a carboxylic acid \( COOH \) and ammonia \( NH_3 \).
2. The alkoxide ion \( O^- \) will be protonated to form \( OH \).

The resulting compound after hydrolysis will be:
\[ CH_3 - CH_2 - C(OH) - CH_3 \]

### Step 4: Elimination to form an alkene
Upon heating, we will undergo a dehydration reaction where water is eliminated. The hydroxyl group \( OH \) and a hydrogen atom from an adjacent carbon will be removed, leading to the formation of an alkene.

The possible elimination can yield two products:
1. \( CH_3 - CH = C - CH_3 \) (but-2-ene)
2. \( CH_3 - C = CH - CH_3 \) (but-1-ene)

However, the more stable product will be the one with the greater number of alkyl substituents on the double bond due to hyperconjugation.

### Step 5: Determine the major product
The major product \( H \) will be:
\[ CH_3 - C = CH - CH_3 \]
This is but-2-ene, which is more stable due to hyperconjugation.

### Final Answer
Thus, the major product \( H \) of the reaction sequence is:
\[ CH_3 - C = CH - CH_3 \]