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For a Cannizzaro reaction R - CHO + Na...

For a Cannizzaro reaction
`R - CHO + NaOH rarr`
Rate law is derived as : `Rate = k [RCHO]^(2) [HO}^(2)`
from the above rate law, it can be concluded that

A

hydride donor is a dianion

B

reaction involved hydride ion transfer

C

reaction does not show kinetic isotopic effect

D

reaction is pseudo `2^(nd)` order

Text Solution

Verified by Experts

The correct Answer is:
A
For formation of dianion hydride donor, an additional mole of `NaOH` is sonsument.

Hence, rate become `2^(nd)` order with respect to `HO` and fourth order overall.
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