What is formed as the major organic product in the reaction?
`CH_(3)CH_(2)-overset(O)overset(||)(C)-NH_(2)+P_(4)O_(10)overset("Heat")to`

Options

A. `CH_(3) CH_(2)NH_(2)`
B. `CH_(3) CH_(2)CH_(2)NH_(2)`
C. `CH_(3) CH_(2)COOH`
D. `CH_(3) CH_(2)CN`

Explanation

To solve the problem, we need to analyze the reaction involving the compound \( CH_3CH_2C(=O)NH_2 \) (an amide) when it reacts with phosphorus pentoxide (\( P_4O_{10} \)) under heat.

### Step-by-Step Solution:

1. **Identify the Reactants**: The reactant is an amide, specifically \( CH_3CH_2C(=O)NH_2 \). This compound has a carbonyl group (C=O) attached to a nitrogen atom (NH2).

2. **Understand the Role of \( P_4O_{10} \)**: Phosphorus pentoxide is a strong dehydrating agent. This means it will remove water (H2O) from the reactants during the reaction.

3. **Dehydration Reaction**: When the amide is heated with \( P_4O_{10} \), it will undergo dehydration. The \( P_4O_{10} \) will remove a molecule of water from the amide, leading to the formation of an unsaturated compound.

4. **Formation of the Product**: The removal of water from the amide will lead to the formation of a nitrile. In this case, the amide \( CH_3CH_2C(=O)NH_2 \) will lose \( H_2O \) and form \( CH_3CH_2C \equiv N \) (propionitrile or ethyl cyanide).

5. **Conclusion**: The major organic product formed from the reaction of the amide with \( P_4O_{10} \) upon heating is \( CH_3CH_2C \equiv N \).

### Final Answer:
The major organic product formed is **propionitrile (ethyl cyanide)**, represented as \( CH_3CH_2C \equiv N \).

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