At higher temperature, iodoform reaction is given by the dilute solution of

Options

A. `CH_(3)CO_(2)CH_(3)`
B. `CH_(3)CO_(2)C_(2)H_(5)`
C. `CH_(3)CO_(2)C_(6)H_(5)`
D. `C_(2)H_(5)CO_(2)CH_(3)`

Answer

B

Explanation

Formation of iodoform is commonly used as a test for alcohola having `-CH(OH)CH_(3)`, grouping, acetaldehyde and ketones having at least one alkyl group as methyl group. i.e., for detecting the presence of `-CHOH. CH_(3) : -COCH_(3)` and `CH_(3) CHO`. The esters (as given in the options) are hydrolsed into alcohol or acids.
`CH_(3) COOC_(2)H_(5) overset (H_(2)O) underset (heat) to CH_(3)COOH + C_(2)H_(5)OH`
Ethyl alcohol so formed will give iodoform test.
`C_(2)H_(5)COOCH_(3) rarr C_(2)H_(5)COOH + CH_(3)`
Hence it will not give iodoform test.