Observe the following reactions, `A+C_6H_5SO_2Cloverset(-OH)tooverset(KOH)to` clear solution `overset(H^(+))to` substance is soluble in aicdic medium
`B+C_6H_5SO_2Cloverset(-OH)to` Insoluble substance in `(H^(+))/(OH^(-))`
`C+C_6H_5SO_2Cloverset(-OH)to` Insoluble in base but soluble in `H^(+)overset(H^(+))to` Clear solution.

Options

A. `1^@`,`3^@` and `2^@` amines
B. `1^@`, `2^@` and `3^@` amines
C. `1^@`, amiline and `2^@` amine
D. `1^@` amine, `2^@` amine and aniline

Answer

B

Explanation

`1^@` amine forms `N-`alkyl benzene sulphonamide with `C_6H_5SO_2Cl`, which if soluble is alkali.
`2^@` amine forms N, N-dialkyl benzene sulphonamide, which is insoluble in alkali as well as acid.
`3^@` amines do not react with `C_6H_5SO_2Cl` and hence are soluble in acid. Thus, A,B and C here represent `1^@,2^@` and `3^@`.