A hydrocarbon `A(C_4H_8)` on reaction with HCl gives a compound `B(C_4H_9Cl)` which on reaction with 1 mole of `NH_3` gives a compound `C(C_4H_(11)N)`. On reacting with `NaNO_2` and `HCl` followed by treatment with water, compound C yields an optically active alcohol,D. Ozonolysisi of A gives 2 moles of acetaldehyde.
The structure of compound C is

Options

A. 2-aminobutane
B. N, N-dimethylenthanamine
C. diethylamine
D. butylamine

Answer

A

Explanation

Such, on ozonolysis, A gives 2 moles of acetaldehyde, so A is `CH_3CH=CHCH_3`
The reaction are as follows