An orgainc compound A upon reacting with `NH_(3)` gives `B` On heating `B` give `C.C` in presence `KOH` reacts with `Br_(2)` to yield `CH_(3)CH_(2)NH_(2) A` is .

Options

A.
B. `CH_3CH_2CH_2CH_2COOH`
C. `CH_3CH_2COOH`
D. `CH_3COOH`

Answer

C

Explanation

`Aoverset(NH_(3))toBoverset(Delta)toCoverset(KOH//Br)toCH_(3)CH_(2)NH_(2)`
The reaction of C with `(KOH)/(Br_2)` to give amine is called hofmann bromamide reaction. This reaction. This reaction is given by acid amides only in which
`R-CH_(2)-overset(O)overset(||)(C)-NH_(2)` Group undergoes rearrangement along with the loss of `CO_2` molecular. Thus the compound C must be acid amide with three carbon atoms. Hence, the compound C is `CH_(3)-CH_(2)-overset(O)overset(||)(C)-NH_(2)`
Since, all the options shows that A is an acid and it forms acid amide on reaction with `NH_3`. thus acid must contain three carbon atoms. Hence the compound A is `CH_3CH_2COOH`. The complete series of reaction can be represented as