In the reduction of nitrobenzene, which of the following is the intermediate

Options

A. `C_6H_5N=O`
B. `C_6H_5NH-NH-C_6H_5`
C. `C_6H_5-N=NC_6H_5`
D.

Explanation

To determine the intermediate formed during the reduction of nitrobenzene, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactant**: The reactant in this case is nitrobenzene (C6H5NO2). It contains a nitro group (-NO2) attached to a benzene ring.

2. **Understand the Reduction Process**: Reduction involves the gain of electrons or hydrogen, or the loss of oxygen. In the case of nitrobenzene, it can be reduced to an amine (aniline, C6H5NH2) using reducing agents like Sn/HCl or Fe/HCl.

3. **Formation of the Intermediate**: During the reduction process, the nitro group (-NO2) is converted to an amine (-NH2) through several steps. The first step typically involves the formation of a hydroxylamine intermediate (C6H5NHOH).

4. **Chemical Reaction**: The reduction can be represented as follows:
- Nitrobenzene (C6H5NO2) + reducing agent → Hydroxylamine (C6H5NHOH) + other products.
- Hydroxylamine can then further reduce to aniline (C6H5NH2).

5. **Identify the Intermediate**: The intermediate formed during the reduction of nitrobenzene is hydroxylamine (C6H5NHOH).

6. **Check Options**: If provided with multiple-choice options, we look for the one that corresponds to hydroxylamine (C6H5NHOH).

### Conclusion:
The intermediate formed during the reduction of nitrobenzene is hydroxylamine (C6H5NHOH).