Total number of `pi` bonds in
`CH_(3)-CH=CH-CH_(2)-C-=CH` is ________.

Options

A. 1
B. 2
C. 3
D. 4

Answer

To determine the total number of π (pi) bonds in the compound CH₃-CH=CH-CH₂-C≡CH, we can follow these steps:

### Step 1: Identify the structure of the compound
The compound can be broken down as follows:
- CH₃ (methyl group)
- CH (part of a double bond)
- CH (part of a double bond)
- CH₂ (part of a single bond)
- C≡CH (part of a triple bond)

### Step 2: Identify the types of bonds present
1. **Single Bonds**: These are sigma (σ) bonds.
2. **Double Bonds**: Each double bond consists of one sigma (σ) bond and one pi (π) bond.
3. **Triple Bonds**: Each triple bond consists of one sigma (σ) bond and two pi (π) bonds.

### Step 3: Count the π bonds
- **Double Bond (CH=CH)**: There is **1 π bond** from the double bond.
- **Triple Bond (C≡CH)**: There are **2 π bonds** from the triple bond.

### Step 4: Sum the π bonds
Now, we add the π bonds from the double and triple bonds:
- From the double bond: 1 π bond
- From the triple bond: 2 π bonds

Total π bonds = 1 + 2 = **3 π bonds**.

### Final Answer
The total number of π bonds in CH₃-CH=CH-CH₂-C≡CH is **3**.

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