Home
Class 12
CHEMISTRY
In NaCl lattice , the radius ratio ...

In `NaCl` lattice , the radius ratio is _______[ Given `: r_(Na^(+))=0.95 Å,r_(Cl^(-))=1.81Å`]

A

`0.22`

B

`0.46`

C

`0.52`

D

`0.47`

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • QUESTION PAPER 2019

    TARGET PUBLICATION|Exercise MCQs|48 Videos

  • SOLUTIONS AND COLLIGATIVE PROPERTIES

    TARGET PUBLICATION|Exercise Evaluation Test|25 Videos

Similar Questions

Explore conceptually related problems

KCl crystallises in the same type of lattices as does NaCl. Given that r_(Na^(+)) //r_(Cl^(-)) = 0.55 and r_(K^(+)) //r_(Cl^(-)) = 0.74 . Calculate the ratio of the side of the unit cell of KCl to that of NaCl.

KCI crystallizes in the same type of lacttice as does NaCl . Given that (r_(Na^(o+)))/(r_(Cl^(Θ))) = 0.5 and (r_(Na^(o+)))/(r_(K^(o+))) = 0.7 Calculate (a) the ratio of side of the unit cell for KCl to that for NaCl , and (b) the ratio of density of NaCl to that KCl .

KCl crystallizes int the same type of lattic as done NaCl . Given that r_(Na^(+))//r_(Cl^(-)) = 0.50 and r_(Na^(+))//r_(K^(+)) = 0.70 , Calcualte the ratio of the side of the unit cell for KCl to that for NaCl:

KCl crystallises in the same type of lattice as does NaCl Given that r_(Na^(+))//r_(Cl^(-))=0.55 and r_(K^(+))//r_(Cl^(-))=0.74 , the ratio of the side of unit cell for KCl to that of NaCl is

KCI cyrstallizes in the saem type of lattice as does NaCl. Given that (r_(Na^(o+))/(r_(Cl_(-)))=0.5 and (r_(Na^(o+)))/(r_(K^(o+)))=0.7 Calculate the ratio of side of the unit cell for KCl to that for NaCl.

CsCl crystallizes in a cubic lattice and has a Cl^(-) at each corner and Cs^(+) at the centre of unit cell. If r_(Cs^(+))=1.69 Å and r_(Cl^(-))=1.81 Å , what is the value of edge - length 'a' of the cube ? Compare this values of 'a' (calculated) from the observed density of CsCl. 3.97 gm//cm^(3). [M_((CsCl))=168.5]