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KCl crystallises in the same type of lat...

KCl crystallises in the same type of lattice as does `NaCl`. Given that `r_(Na^(+))//r_(Cl^(-)) = 0.55 and r_(K^(+))//r_(Cl^(-)) = 0.74`. Calculate the ratio of the side of the unit cell of KCl to that of NaCl

A

`1.122`

B

`1.224`

C

`1.414`

D

`0.732`

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A
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KCl crystallises in the same type of lattices as does NaCl. Given that r_(Na^(+)) //r_(Cl^(-)) = 0.55 and r_(K^(+)) //r_(Cl^(-)) = 0.74 . Calculate the ratio of the side of the unit cell of KCl to that of NaCl.

KCl crystallizes int the same type of lattic as done NaCl . Given that r_(Na^(+))//r_(Cl^(-)) = 0.50 and r_(Na^(+))//r_(K^(+)) = 0.70 , Calcualte the ratio of the side of the unit cell for KCl to that for NaCl:

KCl crystallises in the same type of lattice as does NaCl Given that r_(Na^(+))//r_(Cl^(-))=0.55 and r_(K^(+))//r_(Cl^(-))=0.74 , the ratio of the side of unit cell for KCl to that of NaCl is

KCI crystallizes in the same type of lacttice as does NaCl . Given that (r_(Na^(o+)))/(r_(Cl^(Θ))) = 0.5 and (r_(Na^(o+)))/(r_(K^(o+))) = 0.7 Calculate (a) the ratio of side of the unit cell for KCl to that for NaCl , and (b) the ratio of density of NaCl to that KCl .

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