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The number of atoms in 100 g of an FCC c...

The number of atoms in 100 g of an FCC crystal with density `d = 10 g//cm^(3)` and cell edge equal to 100 pm, is equal to

A

`4xx10^(25)`

B

`3xx10^(25)`

C

`2xx10^(25)`

D

`1xx10^(25)`

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The correct Answer is:
A
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