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When 10 of a non-volatile solute ...

When 10 of a non-volatile solute is dissolved in 100 g of benzene . It raises boiling point by `1^(@)C ` then moler mass of the solute is ______.
(if `K_b` = 2.53 Km^(-1)`

A

`223 g mol ^(-1)`

B

`233 g mol ^(-1)`

C

`243 g mol ^(-1) `

D

`253 g mol ^(-1)`

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The correct Answer is:
D
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10 gram of a non -volatile solute when dissolved in 100 gram of benzene raises its boiling point 1^(@) . What is the molecular mass of the solute ? ( k_(b) for benzene K mol^(-1) ).

The boiling a point of benzene is 353.23K. When 1.80 g of a non-volatile solute was dissolved in 90 g of benzene, the boiling point is raised to 354.11 K. Calculate the molar mass of the solute. K_(b) for benzene is 2.53 K kg mol^(-1) .

The boiling point of benzene is 353 .23 K. When 1.80 gram of non- volatile solute was dissolved in 90 gram of benzene , the boiling point is raised to 354.11 K. Calculate the molar mass of solute . [K_(b) for benzene = 2.53 K kg mol^(-1)]

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