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The depression of freezing point of ...

The depression of freezing point of watar for a particular solution is 0.186 K. The boiling point of the same solution is _______.
`(K_(f)= 1.863= K kg = 0.512 k Kg mol mol^(-1))`

A

`100.186 K`

B

`100.512 K`

C

`273.512 K`

D

`373.0512K`

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The correct Answer is:
D
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