Passage of 96500 coulomb of electricity ...

Passage of 96500 coulomb of electricity liberates …… litre of `O_2` at NTP during electrolysis-

5.6

6.5

22.4

11.2

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96500 culombs of electric current liberates from CuSO_4 solution.

96500C of electricity liberates from CuSO_(4) solution.

The amount of copper in moles deposited by the passage of 96,500 coulombs of electricity through copper sulphate solution is

Gas liberated at cathode during Kolbe's electrolysis is

The charge needed to liberate 67.2 dm^(3) of H_(2) at STP during electrolysis is

How many coulomb are required to liberate 1.12 m^(3) of hydrogen at S.T.P. during electrolysis?

If 96500 coulombs of electricity liberates one gram equivalent of any substance, the time taken for a current of 0.15 amperes to deposite 20 mg of copper from a solution of copper sulphate is (Chemical equivalent of copper = 32)

Electrolysis is the process in which electrical energy is converted to chemical energy. In electrolytic cell, oxidation takes place at anode and reduction at cathode. Electrode process depends on the electrode taken for electrolysis. Amount of substance liberated at an electrode is directly propertional to the amount of charge passed through it. The mass of substance liberated at electrode is calculated using the following relation : m= ("ItE")/(96500) Here, E represents the equivalent mass and 96500 C is called the Faraday constant. Faraday (96500 C) is the charge of 1 mole electron, i.e., 6.023 xx 10^(23) electrons, it is used to liberate one gram equivalent of the substance. Calculate the volume of gas liberated at the anode at STP during the electrolysis of a CuSO_(4) solution by a current of 1 A passed for 16 minutes and 5 seconds :

TARGET PUBLICATION-ELECTROCHEMISTRY-CRITICAL THINKING

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