The electrode where de-electronation tak...

The electrode where de-electronation takes place acts as _________.

anode

cathode

`+ve ` electrode

both (B) and (C)

Text Solution

Verified by Experts

The correct Answer is:

Topper's Solved these Questions

ELECTROCHEMISTRY
TARGET PUBLICATION|Exercise EVALUATION TEST|19 Videos
ELECTROCHEMISTRY
TARGET PUBLICATION|Exercise CRITICAL THINKING|76 Videos
D AND F-BLOCK ELEMENT
TARGET PUBLICATION|Exercise EVALUATION TEST|15 Videos
GENERAL PRINCIPLES AND PROCESSES OF ISOLATION OF ELEMENTS
TARGET PUBLICATION|Exercise Evaluation Thinking|15 Videos

Similar Questions

Explore conceptually related problems

Electrolusis involves electronation and de-electronation at the redpective electrodes. Anode of electrolytic cell is the electrode at which de-electronation takes place whereas at cathode electronation is noticed. If two or more ions of same charge are to be electronated or de-electronated, the ion having lesser discharge potential is dischargeed. Discharge potential of an ion refers for E_(OP)^(@) or E_(RP)^(@) as the case may be. The products formed at either electrode is given in terms of Faraday's laws of electrolysis i.e., w = (E.i.t)/(96500) E. 5 litre solution of 0.4 M Ni(NO_(3))_(2) is electrolysed using Pt electrodes with 2.4125 ampere current for 10 hour:

Electrolusis involves electronation and de-electronation at the redpective electrodes. Anode of electrolytic cell is the electrode at which de-electronation takes place whereas at cathode electronation is noticed. If two or more ions of same charge are to be electronated or de-electronated, the ion having lesser discharge potential is dischargeed. Discharge potential of an ion refers for E_(OP)^(@) or E_(RP)^(@) as the case may be. The products formed at either electrode is given in terms of Faraday's laws of electrolysis i.e., w = (Eit)/(96500) A. During electrolysis of CH_(3)COONa_((aq.)) the mole ratio of gases formed at cathode and anode is :

Electrolusis involves electronation and de-electronation at the redpective electrodes. Anode of electrolytic cell is the electrode at which de-electronation takes place whereas at cathode electronation is noticed. If two or more ions of same charge are to be electronated or de-electronated, the ion having lesser discharge potential is dischargeed. Discharge potential of an ion refers for E_(OP)^(@) or E_(RP)^(@) as the case may be. The products formed at either electrode is given in terms of Faraday's laws of electrolysis i.e., w = (Eit)/(96500) B. During electrolysis of HCOONNa_((aq.)) , the gas liberated at andoe and cathode are respectively:

Electrolusis involves electronation and de-electronation at the redpective electrodes. Anode of electrolytic cell is the electrode at which de-electronation takes place whereas at cathode electronation is noticed. If two or more ions of same charge are to be electronated or de-electronated, the ion having lesser discharge potential is dischargeed. Discharge potential of an ion refers for E_(OP)^(@) or E_(RP)^(@) as the case may be. The products formed at either electrode is given in terms of Faraday's laws of electrolysis i.e., w = (Eit)/(96500) During electrolysis of CuSO_(4(aq.)) , the pH of solution becomes :

Electrolusis involves electronation and de-electronation at the redpective electrodes. Anode of electrolytic cell is the electrode at which de-electronation takes place whereas at cathode electronation is noticed. If two or more ions of same charge are to be electronated or de-electronated, the ion having lesser discharge potential is dischargeed. Discharge potential of an ion refers for E_(OP)^(@) or E_(RP)^(@) as the case may be. The products formed at either electrode is given in terms of Faraday's laws of electrolysis i.e., w = (Eit)/(96500) F. The volume of octane required to be used for its combustion by the oxygen liberated during electrolysis of an NaNO_(3(aq.)) by passing 9.65 ampere current for 1 hr. is :

Electrolusis involves electronation and de-electronation at the redpective electrodes. Anode of electrolytic cell is the electrode at which de-electronation takes place whereas at cathode electronation is noticed. If two or more ions of same charge are to be electronated or de-electronated, the ion having lesser discharge potential is dischargeed. Discharge potential of an ion refers for E_(OP)^(@) or E_(RP)^(@) as the case may be. The products formed at either electrode is given in terms of Faraday's laws of electrolysis i.e., w = (Eit)/(96500) D. 5 litre solution of 0.4 M CuSO_(4(aq.)) is electrolysed using Cu electrode. A current of 482.5 amperer is passed for 4 minute. The concentration of CuSO_(4) left in solution is :

Assertion In an electrolyte cell, the oxidation takes placeat anode while reduction at cathode. Reason De-electronation takes place at anode while electronation takes place at cathode.

TARGET PUBLICATION-ELECTROCHEMISTRY-COMPETITIVE THINKING

In the cell represented by Pb(s)|Pb^(2+)(1 M)||Ag^(+)(1M)|Ag(s) the...
Text Solution
|
De-electronation process in Nernst theory means .
Text Solution
|
The electrode where de-electronation takes place acts as .
Text Solution
|
Standard electrode potential for Sn^(4+)//Sn^(2+) couple is 0.15 V and...
Text Solution
|
Given below are half-cell reactions
Text Solution
|
The cell reaction of a cell is Mg+Cu^(2+) to Mg^(2+)+Cu (Given E(...
Text Solution
|
Standard reduction potential of Au^(3+)//Au and Sn^(4+)//Sn^(2+) elect...
Text Solution
|
The e.m.f of galvanic cell , with oxidation potentials of Zn = +0.76 V...
Text Solution
|
The E(cell)^(@) value for Pt, H(2)|H^(+)||Ag^(+)|Ag is . [E(Ag//Ag^(+)...
Text Solution
|
In the cell Zn|Zn^(2+)(1M)||H^(+)(1M)|H(2(g))|Pt Zn electrode is repla...
Text Solution
|
The e.m.f of the following cell, Zn |ZnSO(4) (1M)||H^(+)(1M)|H(2(g))...
Text Solution
|
For the electrochemicl cell, M|M^(+)||X^(-)|X E((M^(+)//M))^(@) = 0.44...
Text Solution
|
At temperature of 298 K , the e.m.f. of the following electrochemical ...
Text Solution
|
In the electrochemical cell: Zn|ZnSO(4)(0.01 M)||CuSO(4)(1.0M)|Cu ...
Text Solution
|
Standard electrode potentials are Fe^(2+)//Fe, E^(@) = -0.44 V Fe^...
Text Solution
|
Nernst equation for Zn((aq))^(2+)+2e^(-) to Zn((s)) is E(Zn^(2+)//Zn) ...
Text Solution
|
Given E(Cr^(3+)//Cr)^(@)=-0.72V, and E(Fe^(2+)//Fe)^(@)=-0.42V The...
Text Solution
|
The cell , Zn | Zn^(2+) (1M) || Cu^(2+) (1M) Cu (E("cell")^@ = 1. 10 V...
Text Solution
|
What will be the emf for the given cell ? Pt|H(2)(g,P(1))|H^(+)(aq)|...
Text Solution
|
The reduction potential of hydrogen half cell will be negative if :
Text Solution
|