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In the electrochemical cell: Zn|ZnSO(4...

In the electrochemical cell:
`Zn|ZnSO_(4)(0.01 M)||CuSO_(4)(1.0M)|Cu`
The EMF of this Daniel cell is `E_(1)`. When the concentration of `ZnSO_(4)` is changed to 1.0(M) and that of `CuSO_(4)` changed to 0.01(M), the EMF changes to `E_(2)`. From the following which one is the relationship between `E_(1) and E_(2)" "("Given, "(RT)/(F)=0.059)`-

A

`E_(1) lt E_(2)`

B

`E_(1) gt E_(2)`

C

`E_(2)= 0 ne E_(1)`

D

`E_(1) =E_(2)`

Text Solution

Verified by Experts

The correct Answer is:
B
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