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In triangle ABC , angle BAC = 90^(@) ...

In ` triangle ABC , angle BAC = 90^(@) ` , seg BL and seg CM are medians of ` triangle ABC ` . Then prove that
` 4 (BL^(2) + CM^(2)) = 5 BC^(2)`

Text Solution

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The correct Answer is:
`therefore4(BL^(2)+CM^(2))=5BC^(2)`
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