`Delta ABC` is an equilateral triangle. Point P is on base BC such that `PC = 1/3 BC,` if `AB = 6` cm find AP.

Delta ABC is an equilateral triangle.Point P is on base BC such that PC=(1)/(3)BC, if AB=6cm find AP.

DeltaABC is an equilateral triangle. Point P is on base BC such PC=(1)/(3) BC, if AB=6 cm find AP.

The perimeters of two similar triangles are 25cm and 15cm respectively. If one side of the first triangle is 9cm, find the length of the corresponding side of the second triangle. OR In an equilateral triangle ABC, D is a point on side BC such that BD = 1/3 BC. Prove that 9 AD^(2)=7AB^(2)

In an equilateral triangle ABC,D is a point on side BC such that BD=(1)/(3)BC Prove that 9AD^(2)=7AB^(2)

M is the midpoint of side AB of equilateral triangle ABC.P is a point on BC such that (AP+PM) is minimum.If AB=20 then AP+PM is

DeltaABC is an equilateral triangle, AB = 6. The points P, Q and Rare midpoints of AB, BC and CA respectively. The perimeter of PBCR is