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The circumferences of circular faces of ...

The circumferences of circular faces of frustum are 132 cm and 88 cm and its height is 24 cm. To find the curved surface area of frustum, complete the following activity. `(pi = 22/7)`

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The correct Answer is:
`= 2750 cm^(2)`
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The circumferences of circular faces of a frustum are 132 cm and 88 cm and its height is 24 cm. To find the slant height of the frustum complete the following activiy. (pi=22/7) "circumference"_1=2pir_1=132 r_1=132/(2pi)=square "circumference"_2=2pir_2=88 r_2=88/(2pi) =square Slant height of frustum, l=sqrt(h^2+(r_1-r_2)^2) =sqrt(24^2+square^2) = squarecm

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