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In DeltaABC, ray BD bisects /ABC. A-D-C,...

In `DeltaABC`, ray `BD` bisects `/_ABC`. `A-D-C`, side `DE||` side `BC`, `A-E-B`.
Prove that, `(AB)/(BC)=(AE)/(EB)`.
Complete the activity by filling the boxes.

In `DeltaABC`, ray `BD` is the bisector of `/_ABC`
`:.(AB)/(BC)=square`.......`(I)` (By angle bisector theorem)
In `DeltaABC`, seg `DE||` side `BC`
`:.(AE)/(EB)=(AD)/(DC)`........`(II)` `square`
`:.(AB)/(square)=(square)/(EB)`.......[From `(I)` and `(II)`]

Answer

Step by step text solution for In DeltaABC, ray BD bisects /_ABC. A-D-C, side DE|| side BC, A-E-B. Prove that, (AB)/(BC)=(AE)/(EB). Complete the activity by filling the boxes. In DeltaABC, ray BD is the bisector of /_ABC :.(AB)/(BC)=square.......(I) (By angle bisector theorem) In DeltaABC, seg DE|| side BC :.(AE)/(EB)=(AD)/(DC)........(II) square :.(AB)/(square)=(square)/(EB).......[From (I) and (II)] by MATHS experts to help you in doubts & scoring excellent marks in Class 10 exams.

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Knowledge Check

  • In the adjoning figure of DeltaABC, AD is the perpendicular bisector of side BC. The triangle ABC is :

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    B
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    C
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