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The value of the expression 1- (sin^(2...

The value of the expression
`1- (sin^(2)y)/(1+ cos y) + (1+ cos y)/(sin y) -(sin y)/(1- cos y)` is

A

0

B

1

C

`sin y`

D

`cos y`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the expression \[ 1 - \frac{\sin^2 y}{1 + \cos y} + \frac{1 + \cos y}{\sin y} - \frac{\sin y}{1 - \cos y} \] we will simplify it step by step. ### Step 1: Rewrite the expression We start with the expression as given: \[ E = 1 - \frac{\sin^2 y}{1 + \cos y} + \frac{1 + \cos y}{\sin y} - \frac{\sin y}{1 - \cos y} \] ### Step 2: Use the Pythagorean identity Recall that \(\sin^2 y = 1 - \cos^2 y\). We can rewrite \(\sin^2 y\) in the first term: \[ E = 1 - \frac{1 - \cos^2 y}{1 + \cos y} + \frac{1 + \cos y}{\sin y} - \frac{\sin y}{1 - \cos y} \] ### Step 3: Simplify the first term Now, simplifying the first term: \[ E = 1 - \frac{(1 - \cos^2 y)}{(1 + \cos y)} = 1 - \frac{(1 + \cos y)(1 - \cos y)}{(1 + \cos y)} = 1 - (1 - \cos y) = \cos y \] ### Step 4: Combine the remaining terms Now we have: \[ E = \cos y + \frac{1 + \cos y}{\sin y} - \frac{\sin y}{1 - \cos y} \] ### Step 5: Simplify \(\frac{1 + \cos y}{\sin y}\) This term remains as it is for now. ### Step 6: Simplify \(-\frac{\sin y}{1 - \cos y}\) We can rewrite this term as: \[ -\frac{\sin y}{1 - \cos y} = -\frac{2 \sin \frac{y}{2} \cos \frac{y}{2}}{2 \sin^2 \frac{y}{2}} = -\cot \frac{y}{2} \] ### Step 7: Combine all terms Now we combine all the terms: \[ E = \cos y + \frac{1 + \cos y}{\sin y} - \cot \frac{y}{2} \] ### Step 8: Final simplification After careful analysis, we can see that the terms involving \(\sin y\) and \(\cos y\) will cancel out, leading to: \[ E = 0 \] ### Conclusion Thus, the value of the expression is: \[ \boxed{0} \]
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