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If x = sec phi - tan phi and y = cos ec ...

If `x = sec phi - tan phi` and `y = cos ec phi + cot phi` , then

A

`x= (y+1)/(y-1) `

B

`x= (y-1)/(y+1)`

C

`y=(1-x)/(1+x)`

D

`y= (1+x)/((1-x)^(2))`

Text Solution

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The correct Answer is:
B
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