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If sintheta=(2t)/(1+t^2) and theta lies ...

If `sintheta=(2t)/(1+t^2)` and `theta` lies in 2nd quadrant ,then `costheta` is equal to

A

`(1- t^(2))/(1+t^(2))`

B

`(t ^(2)-1)/(1+t^(2))`

C

`(-|t-t ^(2)|)/(1+t^(2))`

D

`(1+ t ^(2))/(|1- t ^(2)|)`

Text Solution

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The correct Answer is:
C
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TARGET PUBLICATION-TRIGONOMETRIC FUNCTIONS -COMPETITIVE THINKING
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