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If t a ntheta+s e ctheta, then costheta ...

If `t a ntheta+s e ctheta,` then `costheta` equals `(e^x+e^(-x))/2` (b) `2/(e^x+e^(-x))` (c)`(e^x-e^(-x))/2` (d) `(e^x-e^(-x))/(e^x+e^(-x))`

A

`((e ^(x) +e^(-x)))/(2)`

B

`(2)/((e ^(x) +e ^(-x))`

C

`((e ^(x) -e^(-x)))/(2)`

D

`(e^(x)-e ^(-x))/((e^(x) +e^(-x))`

Text Solution

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The correct Answer is:
B
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TARGET PUBLICATION-TRIGONOMETRIC FUNCTIONS -COMPETITIVE THINKING
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